One thing that the trailer of Doctor Strange in the Multiverse of Madness has clearly pointed out is that Wanda Maximoff will definitely be portrayed as a negative character in the movie. The Scarlet Witch will go completely rogue in an attempt to find her lost sons in the Multiverse and Doctor Strange will have to fight her at some point in the movie to stop the chaos that has been created by her.
The Producer of Doctor Strange in the Multiverse of Madness has now made a big revelation about the faceoff between these two heavyweight magicians and it has intensified our excitement for the movie Tenfolds.
Doctor Strange vs Wanda Maximoff
Doctor Strange in the Multiverse of Madness producer Richie Palmer recently said in an interview that the movie will have an epic final battle between Doctor Strange and Scarlet witch a.k.a Wanda Maximoff. He also went on to say that his money will definitely be on Scarlet Witch as the power that she showed in Avengers: Endgame, when she tormented Thanos completely, were outstanding. Moreover, she has grown more powerful than ever after assuming the powers of Agatha Harkness and getting hold of the Book of Darkhold.
“Meeting the Wanda Maximoff at the end of Endgame would have been a lot for Strange. Who comes out on top as the most powerful being in the universe? Maybe we find out atFinal Battle at Wundagore Mountains
Final Battle at Wundagore Mountains
Fan Theories has suggested long ago that Doctor Strange and Wanda Maximoff will probably have a battle near the Wundagore Mountain, where Chhthon wrote the Book of Darkhold. In a particular scene from the trailer, we see America Chavez punching through a star-shaped portal inside a cavern that has designed just like that of the Book of Darkhold on it. People think that it is actually the inside of the Wundagore Mountains and Scarlet Witch has trapped them inside.
Moreover, the Zombie Strange TV Spot footage shows a Mountain top which again hints that Scarlet Witch and Doctor Strange will indeed fight in front of the Wundagore Mountains.